CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

The number of even proper divisors of 1008 is


A

23

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

21

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

20

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

23


Explanation for the correct option:

Find the total number of divisors of the given number.

A number 1008 is given.

The factors of the given number are as follows 1008=223·32·7.

So, the even divisors are as follows: (3+1)(2+1)(1+1)=24

So, the number of proper even divisors can be given by 24-1=23.

Therefore, the total number of proper even divisors of the given number is 23.

Hence, option A is the correct answer.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Different Categories in PNC
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon