The number of factors of number N- 23- 32- 53 is

The correct option is B 48 Number of factors of N #160; (2^3× 3^2× 5^3)=(3+1)× (2+1)× (3+1)=4× 3× 4=48 ...

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Factorial

The number of...

Question

The number of factors of number $N = 2^{3} \times 3^{2} \times 5^{3}$ is

18

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45

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48

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9

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N = 2^{3} \times 3^{2} \times 5^{3} \times 10.

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