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Nernst Equation

The number of...

Question

The number of Faradays $(F)$ required to produce $9 g$ of aluminium from molten $A l C l_{3}$ is
(Atomic mass of $A l = 27 {g mol}^{- 1})$

2

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3

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1

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4

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Solution

The correct option is C $1$
Equivalent wt of aluminium $= 9$
Number of equivalent of aluminium deposited at cathode $= \frac{9}{9} = 1$
Number of Faraday required $= 1$

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