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Question

The number of Faradays needed to reduce 4 g equivalents of Cu2+ to Cu metal will be:

A
1
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B
2
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C
1/2
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D
4
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Solution

The correct option is D 4
According to mole concept:
1 mole of an atom contains number of particles.
We know that:
Charge on 1 electron ==1.6×1019C
Charge on 1 mole of electrons =1.6×1019×6.022×1023=96500C (96500C=1 Faraday)

Q=i×t
where Q= quantity of electricity in coulombs
I = current in amperes
t= time in seconds

Cu2++2eCu
2 g equivalent of Cu(II) requires 2 Faraday of electricity
4 g equivalent of Cu(II) requires =4 Faraday of electricity

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