The number of feet of normals from the point $(7, - 4)$ to the circle $x^{2} + y^{2} = 5$ is

1

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2

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3

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4

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Solution

The correct option is B $2$
Clearly, $(7, - 4)$ is an external point to the circle $x^{2} + y^{2} = 5$ and normal drawn from an external point passes through the center and hence, intersects the circle at 2 points.

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