The number of five digit numbers that can be formed with 0,1,2,3,5 which are divisible by 5 is:
A
24
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B
42
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C
48
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D
60
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Solution
The correct option is B42 Total no. of arrangements with 5 or 0 is last digit. 43212 So, total no. of arrangements =4×3×2×2=48. Total no. of arrangements with 5 as last digit and 0 as first digit, that are to be excluded =3×2×1=6. 03215
So, total number of five digit numbers that can be formed, thus =48−6 =42