The number of five digit numbers that can be formed with 0,1,2,3,5 which are divisible by 25 is
A
42
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B
24
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C
10
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D
38
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Solution
The correct option is C10 The required 5 digit numbers should have 25 or 50 in the end. The total number of 5-digit numbers containing 25 in the end will be ...(no repetition of digits) 3!. Of these the number of numbers containing 0 from the beginning are 2!,2! due to internal permutations. Hence, total number of 5 digit number with 25 in the end using the given set of 5 number are 3!−2! ...(no repetition of digits) =4 ...(i) Now the total number of 5 digit numbers with 50 at the end =3! ....(no repetition of digits)...(ii) Hence, the total number of 5 digit numbers formed using 0,1,2,3,5 without repetitions of digits, and divisible by 25 are 3!+4 =6+4 =10