Question

The number of four digit numbers formed by using the digits $0,2,4,5$ and which are not divisible by $5$, is

• A. $10$
• B. $8$
• C. $6$
• D. $4$

Answer 1

The correct option is B $8$

No. of four digit numbers divisible by $5$
no.ending in '$0$' are
$\underset{–}{}\underset{–}{}\underset{–}{}\underset{–}{0}\Rightarrow 3!=6$
no. ending in '$5$ '( will not have 1st digit as '$0$')
$\underset{–}{}\underset{–}{}\underset{–}{}\underset{–}{5}\Rightarrow 3!-2!=4$
Total No. of four digit numbers $=4!-3!=18$
$\therefore$ Required no.s$=18-(6+4)=8$