CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of four digit numbers that can be formed from the digits 2,3,5,6,7,8 so that the digits do not repeat and the terminal digits are even is

A
42
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
B
78
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
C
72
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
36
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
E
None of these
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
Open in App
Solution

The correct option is C 72

If the first digit and last digit of the four digit number needs to be even, then we have to choose numbers out of 2, 6 and 8

The first digit can be chosen in 3 ways and the last digit in 2 ways = 3×2=6 ways

The remaining two digits can be chosen and arranged among the remaining 4 digits in 4P2 ways = 12 ways

Total number of ways = 6×12=72 ways


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutation
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon