Question

The number of g-atom of oxygen in $6.02\times {10}^{24}$ $CO$ molecule is

• A. $1$
• B. $0.5$
• C. $5$
• D. $10$

Answer 1

The correct option is D $10$

One molecule of $CO$ contains one oxygen atom
$\therefore 6.02\times {10}^{24}$ molecules of $CO$ contain $6.02\times {10}^{24}$ oxygen atoms
$6.02\times {10}^{23}$ atoms of oxygen $\equiv$ $1g$ atom of oxygen
$\therefore 6.02\times {10}^{24}$ atoms of oxygen $\equiv$ $10g$ atom of oxygen.