Question

The number of g molecules of oxygen in $6.022\times {10}^{24}$ CO molecule is:

• A. 1 g molecule
• B. 0.5 g molecule
• C. 5 g molecule
• D. 10g molecule

Answer 1

The correct option is C 5 g molecule

$6.022\times {10}^{23}$ molecules of CO contains 0.5 g molecule of oxygen
$6.02\times {10}^{24}$ molecules of CO would contain = $\frac{(0.5\times 6.02\times {10}^{24})}{6.022X{10}^{23}}=5g$ molecules of oxygen