Question

The number of $g$ molecules of oxygen in $6.023\times {10}^{24}CO$ molecules is ________________.

• A. $1g$ molecule
• B. $0.5g$ molecule
• C. $5g$ molecules
• D. $10g$ molecules

Answer 1

The correct option is C $5g$ molecules

$1$ mole of $CO=6.023\times {10}^{23}$ molecules

$x$ mole of $CO=6.023\times {10}^{24}$ molecules

$\therefore x=10$ moles $=10g$ molecules

$CO=1$ oxygen atom

$\therefore$ Oxygen molecules $=\frac{10}{2}$

$=5g$ molecules

Option $C$ is correct.