Question

The number of geometric isomers that can exist for square planar $\left[Pt\right(Cl\left)\right(py\left)\right(N{H}_3\left)\right(N{H}_{2}OH){]}^{+}$ is:

• A. 2
• B. 3
• C. 4
• D. 6

Answer 1

Answer: (B)

3

$\left[Pt\right(Cl\left)\right(py\left)\right(N{H}_3\left)\right(N{H}_{2}OH){]}^{+}$ is square planar complex. The structure is formed by fixing a group and then arranging all the groups.

Hence, this complex shows three geometrical isomers.

The correct answer is option $B$.