CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Linkage Isomerism

The number of...

Question

The number of geometrical isomer(s) possible for $[A u C l_{2} B r_{2}]$ (square) planar is/are :

Open in App

Solution

The correct answer is 2. $[A u C l_{2} B r_{2}]$ is a $[M a_{2} b_{2}]$ type square planar complex ion, it has two geometrical isomers viz cis and trans isomers.

Suggest Corrections

thumbs-up

0

Similar questions

Q. How many geometrical isomers are there for

[C o (N H_{3})_{2} C l_{4}]^{-}

(octahedral) and

[A u C l_{2} B r_{2}]

(square planar)?

Q. For the square planar complex [Mabcd] where M is the central atom and a,b,c,d are monodentate ligands, the number of possible geometrical isomers are:

Q. For the square planar complex,

[M (a) (b) (c) (d)]

=

central metal and a, b, c and d are monodentate ligands), the number of possible geometrical isomers are:

Q. The number of geometrical isomers for square planar

[A u B r_{2} C l_{2}]^{-}

[P t C l_{2} (e n)] are respectively:

Q. The number of geometrical isomers for octahedral

{[C o C l_{4} {(N H_{3})}_{2}]}_{4}^{-}

, square planar

{[A u B r_{2} C l_{2}]}_{2}^{-}

[P t C l_{2} (e n)]

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Linkage Isomerism

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Linkage Isomerism

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon