Question

The number of geometrical isomers for square planar $[AuB{r}_{2}C{l}_2{]}^{-}$ and $\left[PtC{l}_2\right(en\left)\right]\text{are respectively:}$

• A. $2,2$
• B. $2,$ no isomerism
• C. $3,2$
• D. $3,$ no isomerism

Answer 1

The correct option is B $2,$ no isomerism

In Square planar $[AuB{r}_{2}C{l}_2{]}^{-}$ complex, both Br can be located at adjacent position or at opposite positive to give cis and trans isomers respectively. Hence, they have 2 geometrical isomers.

In square planar $\left[PtC{l}_2\right(en\left)\right]$, the symmetrical bidentate ligand ethylenediamine locate at adjacent position, so there is not possibility for the Cl ligand to be at opposite position. Hence, it does not show geometrical isomerism.