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Question

The number of geometrical isomers for square planar [AuBr2Cl2]− and [PtCl2(en)] are respectively:

A
2,2
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B
2, no isomerism
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C
3,2
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D
3, no isomerism
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Solution

The correct option is B 2, no isomerism
In Square planar [AuBr2Cl2] complex, both Br can be located at adjacent position or at opposite positive to give cis and trans isomers respectively. Hence, they have 2 geometrical isomers.

In square planar [PtCl2(en)], the symmetrical bidentate ligand ethylenediamine locate at adjacent position, so there is not possibility for the Cl ligand to be at opposite position. Hence, it does not show geometrical isomerism.

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