The number of geometrical isomers formed by ${[C o {({N H}_{3})}_{4} {({N O}_{2})}_{2}]}_{4}^{+}$ is

2

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3

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4

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0

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Solution

The correct option is A $2$
${[C o {({N H}_{3})}_{4} {({N O}_{2})}_{2}]}_{4}^{+}$ exists in 2 geometrical isomeric forms - cis and trans form.

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