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The number of geometrical isomers found in the metal complexes [Pt(Cl)2(NH3)2],[Ni(CO)4],[Ru(H2O)3Cl3] and[CoCl2(NH3)4]+ respectively, are

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Solution

[Pt(Cl)2(NH3)2] forms two possible geometrical isomers, cis and trans.
In cis, same group on same side and in trans same groups on opposite side.


In [Ni(CO)4], the oxidation state of Ni is 0 and it forms a outer orbital complex with sp3 hybridisation. Thus, it form tetrahedral complex and it lacks geometrical isomerism.

In [Ma3b3] type of complex, the possible geometrical isomers are two, facial and meridional.
Facial isomer have three identical ligands on one triangular face.
Meridional isomer have three identical ligands in a plane bisecting the molecule.



In [Ma2b4] type, there are two possible geomerical isomers, cis and trans.
These isomers are given below,


Hence, option (c) is correct.

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