The number of geometrical isomers in the following compound is:
$C H_{3} - C H = C H - C H = C H - C_{2} H_{5}$

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Solution

The correct option is A 4
The given compound is a unsymmetrical compound. It has different terminal groups.
The formula used to determinne the number of geometrical isomers in compound having different terminal groups is, $2^{n}$ , where n is the number of dounle bond present in the molecule.
In the given compound we have 2 double bond so n = 2
Therefore,
No. of geometrical isomers = $2^{n}$
= $2^{2}$
= 4.

Hence, unsymmetrical compound with 2 double bonds has 4 stereoisomers.

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