The number of geometrical isomers in the following compound is:
$C H_{3} - C H = C H - C H = C H - C_{2} H_{5}$

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Solution

The correct option is A 4
The given unsymmetrical compound with 2 double bonds is $C H_{3} - C H = C H - C H = C H - C_{2} H_{5}$
All possible geometrical isomers are

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C H_{3} - C H = C H - C H = C H - C_{2} H_{5}

C H_{3} - C H = C H - C H = C H - C_{2} H_{5}

C H_{3} - C H = C H - C H = C H - C H_{3}

B r - C H = C H - C H_{2} - C H = C H - C H_{2} - C H = C = C = C H - C H = C (C H_{3})_{2}

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