The number of geometrical isomers of $C H_{3} C H = C H - C H = C H - C H = C H - C l$ is :

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Solution

The correct option is D 8
Since both the C atoms of the 3 double bonds are differently substituted, therefore $2^{3} = 8$ geometrical isomers.

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Similar questions

The number of geometrical isomers of

$C H_{3} - C H = C H - C H = C H - C H = C H C L$ is

C H_{3} - C H = C H - C H (B r) - C H_{2} - C H_{3}

C H_{3} - C H = C H - C H = C H - C H_{3}

C H_{3} - C H = C H - C H = C H - C l

C H_{3} - C H = C H - C H = C H - C H = C H - C H_{3}

(i) {C H}_{3} - C H = C H - C H = C H - {C H}_{3}

(i i) {C H}_{3} - C H = C H - C H = C H - C l

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