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Geometrical Isomerism in Square Planar Geometry

The number of...

Question

The number of geometrical isomers of the complex $[C o C l_{3} (N H_{3})_{3}]$ is

A

2

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B

3

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C

4

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Solution

The correct option is A 2
$[M A_{3} B_{3}]$ type complex, shows facial and meridional isomers

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Similar questions

Q. The number of geometrical isomers of the complex

[C o (N O_{2})_{3} (N H_{3})_{3}]

Q. Total number of geometrical isomers for the complex

[R h C l (C O) (P P h_{3}) (N H_{3})]

Q. The number of geometrical isomers of

C H_{3} C H = C H - C H = C H - C H = C H - C l

Q. How many geometric isomers are possible:

[C o C l_{3} (N H_{3})_{3}]

Q. The number of geometric isomers that can exist for square planar

[P t (C l) (p y) (N H_{3}) (N H_{2} O H)]^{+}

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