The number of girls appearing for an admission test is twice the number of boys. If 30% of the girls and 45% of the boys get admission, the percentage of condidates who do not get admission is

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Solution

The correct option is D
65

Let the number of boys be b.
Then, number of girls = 2b
Therefore, percentage of candidates not getting admission $= [\frac{(0.7 \times 2 b + 0.55 b)}{3 b}] \times 100 = 65$

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The number of girls appearing for an admission test is twice the number of boys. If 30% of the girls and 45% of the boys get admission, the percentage of condidates who do not get admission is

The correct option is D 65 Let the number of boys be b. Then, number of girls = 2b Therefore, percentage of candidates not getting admission =[(0.7×2b+0.55b)3b]×100=65

The correct option is D
65

Let the number of boys be b.
Then, number of girls = 2b
Therefore, percentage of candidates not getting admission $= [\frac{(0.7 \times 2 b + 0.55 b)}{3 b}] \times 100 = 65$