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Question

The number of girls in a class is 4 more than the number of boys. On a day when only 8 boys were absent, the numbers of girls were double the number of boys. How many girls and boys are there in that class?

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Solution

Let the number of boys in the class be x and the number of girls in the class be y.

The number of girls in the class is four more than the number of boys.

y = x + 4 … (1)

Number of boys absent on a particular day = 8

Number of boys present on that day = x − 8

According to the question:

2(x 8) = y

2x 16 = y

2x y = 16

Putting the value of y from equation (1):

2x (x + 4) = 16

2x x 4 = 16

x = 16 + 4

x = 20

From equation (1), we have:

y = 20 + 4 = 24

Thus, there are 20 boys and 24 girls in the class.


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