The number of girls in school A is approximately what percentage of the total number of students in school B?

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Solution

The correct option is E
41

Number of girls in school A $= \frac{6000 \times 12}{1000} - 500 = 720 - 500 = 220$

Number of students in school B $= \frac{6000 \times 9}{1000} = 540$

$∴$ Required percentage $= \frac{220}{540} \times 100 = 41$

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The number of girls in school A is approximately what percentage of the total number of students in school B?

The correct option is E 41 Number of girls in school A =6000 ×121000–500=720–500=220 Number of students in school B =6000 ×91000=540 ∴ Required percentage =220540×100=41

The correct option is E
41

Number of girls in school A $= \frac{6000 \times 12}{1000} - 500 = 720 - 500 = 220$

Number of students in school B $= \frac{6000 \times 9}{1000} = 540$

$∴$ Required percentage $= \frac{220}{540} \times 100 = 41$