Question

The number of gram equivalents in $250mL$ of $0.25NKOH$ solution is :

• A. 1
• B. 0.0625
• C. 0.625
• D. 0.1

Answer 1

The correct option is B 0.0625

Since
$\text{Normality}=\frac{\text{Number of gram equivalents of solute}}{\text{Volume of solution (L)}}$
$\text{Volume}=250mL=\frac{250}{1000}L\text{Volume}=0.25L$

$\text{Normality}\times \text{Volume of solution (L)}=\text{Number of gram equivalents of KOH}\text{Number of gram equivalents of KOH}=0.25\times 0.25\text{Number of gram equivalents of KOH}=0.0625$