Question

The number of gram molecules of oxygen in $6.02\times {10}^{24}CO$ molecules is :

• A. $10$ gram molecules
• B. $5$ gram molecules
• C. $1$ gram molecules
• D. $0.5$ gram molecules

Answer 1

The correct option is B $5$ gram molecules

The number of gram atoms of oxygen in $6.02\times {10}^{24}CO$ molecules is obtained by dividing $6.02\times {10}^{24}$ with Avogadro's number.

$\frac{6.02\times {10}^{24}}{6.02\times {10}^{23}}=10$.

The number of gram molecules of oxygen $\left(O_2\right)$ is equal to one half the number of gram atoms of oxygen. It is $\frac{10}{2}=5$.

The number of gram molecules of oxygen in $6.02\times {10}^{24}CO$ molecules is 5-gram molecules.

Hence, the correct option is $\text{B}$