The number of grams of $H_{2} S O_{4}$ present in 0.25 mole of $H_{2} S O_{4}$ is:

4.95 g

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2.45 g

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24.5 g

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49.0 g

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Solution

The correct option is C 24.5 g
1 mole of $H_{2} S O_{4}$ = 98g
0.25 mole of $H_{2} S O_{4}$ = $98 * 0.25$ = 24.5g

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The number of moles present in $24.5 g m s$ of $H_{2} S O_{4}$ is

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