Question

The number of hydrogen atoms present in $25.6gm$ of sucrose $\left(C_{12}{H}_{22}{O}_{11}\right)$ is:

• A. $1.8N_A$
• B. $1.64N_A$
• C. $2.38N_A$
• D. $1.0N_A$

Answer 1

The correct option is B $1.64N_A$

We have molecular formula of sucrose as $C_{12}{H}_{22}{O}_{11}$,

so, 1 mole of sucrose have 11 moles of hydrogen atoms present in it,

so, we can say that

number of hydrogen atom present in 342 g(1 mole) of sucrose = $22\ast N_A$

so, number of hydrogen atom in 25.6 g of sucrose = $\frac{22\ast N_A}{342}\ast 25.6=1.64N_A$