The number of hydrogen bonds present in the sequence of a stretch of a double helical DNA 51 ATGCCTAA 31, is:
A
16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
19
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
24
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 19 The number of hydrogen bonds present in the sequence of a stretch of a double helical DNA 51 ATGCCTAA 31 is 19. A always combines with T by two hydrogen bonds and G combines with C by three hydrogen bonds. Thus, we can simply sum them up to get the required result.