The number of integer values of m, for which the x co-ordinate of the point of intersection of the lines 3x+4y=0 and y=mx+1 is also an integer, is
Solve both eqns simply and take out (x,y) coordinates.put y = mx +1 in 3x + 4y – 9 = 0U would get,3x + 4(mx + 1) – 9 = 0(3 + 4m)x = 6x = > 6/(3 + 4m)and y = 6m/(3+4m) + 1 = > (7m +3)/(3+4m)Now for x to be integer,the modulus of denominator value should not be greater equals than 6.Therefore,(3+4m) less than equal to 6 and greater than -6on solving m would satify asm = 0, -1 .