The number of integers greater then 6000 that can be formed, using the digits 3,5,6,7 and 8, without repetition, is: -

120

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216

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192

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Solution

The correct option is D 192
Four digits number can be arranged in $3 \times 4!$ ways.
Five digits number can be arranged in 5! ways.
Number of integers $= 3 \times 4! + 5! = 192$

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