The number of integers n with 100 - n - 999 and containing at most two distinct digits is -

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Standard XI

Mathematics

Permutation under Restriction

The number of...

Question

The number of integers n with $100 \leq n \leq 999$ and containing at most two distinct digits is :

252

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Solution

The correct option is A 252
Total 3 digits numbers are $900$
Also, numbers having all the digits distinct would be $9 \times 9 \times 8 = 648$
Thus, the remaining numbers containing at most two distinct digits are $900 - 648 = 252$

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The number of integers n with 100≤n≤999 and containing at most two distinct digits is :

The correct option is A 252Total 3 digits numbers are 900Also, numbers having all the digits distinct would be 9×9×8=648Thus, the remaining numbers containing at most two distinct digits are 900−648=252

The number of integers n with $100 \leq n \leq 999$ and containing at most two distinct digits is :

The correct option is A 252
Total 3 digits numbers are $900$
Also, numbers having all the digits distinct would be $9 \times 9 \times 8 = 648$
Thus, the remaining numbers containing at most two distinct digits are $900 - 648 = 252$