The number of integers of the form 3AB4, where A, B denote some digits, which are divisible by 11 is
A. 0
B. 4
C. 7
D. 9
The number is of the form 3AB4.
Here, 3 − A + B − 4 = B − A − 1
3AB4 is divisible by 11 if B − A − 1 is divisible by 11.
B − A − 1 is divisible by 11.
⇒ B − A − 1 = 0 or 11
⇒ B − A = 1 or 10
However, B − A cannot be equal to 10 as A and B are digits.
∴ B − A must be 1.
Therefore, the possible values of A and B are (1, 0), (2, 1), (3, 2), (4, 3), (5, 4), (6, 5),
(7, 6), (8, 7) and (9, 8)
Hence, the correct answer is D.