The number of integers x for which x, 10 and 24 are the sides of an acute angled triangle is
A
2
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B
3
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C
4
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D
9
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Solution
The correct option is A
2
For an acute angled triangle, l2 <m2 +n2
where l is the largest side length among the side lengths of the triangle, l, m and n. We have 2 cases for the integer x.
Case I.X>24>10 X2 <242+102 X2 <676 ⇒ x ≤25 Butx+10>24 X > 14 ∴ x can take integer values from 15 to 25. Only 25>24. Hence, there Is only 1 value of x in this case. Case. II.24>X>10 242<x2+102 476<X2 ⇒X≥22 Butx<24 Hence x can take values 22, 23. There are two possibilities in this case. Note :Also when x=24, we can have an isosceles acute angled triangle.