The number of integral points (integral point means both the coordinates should be integer) exactly in the interior of the triangle with vertices (0,0), (0,21)and (21,0) is

133

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190

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233

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105

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Solution

The correct option is B 190
Total no. of points withn the square OABC $= 20 \times 20 = 400$

Points on line AB = OC = 20 {(1,1),2,2), .......(20,20)}
$∴$ Points within $Δ O B C$ and $Δ A B C$ = 400 - 20 = 380
By symmetry points within $Δ O A B = \frac{380}{2} = 190$

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The number of integral points (integral point means both the coordinates should be integer) exactly in the interior of the triangle with vertices (0,0), (0,21)and (21,0) is

The correct option is B 190Total no. of points withn the square OABC =20×20=400 Points on line AB = OC = 20 {(1,1),2,2), .......(20,20)} ∴ Points within ΔOBC and ΔABC = 400 - 20 = 380 By symmetry points within ΔOAB=3802=190

The correct option is B 190
Total no. of points withn the square OABC $= 20 \times 20 = 400$

Points on line AB = OC = 20 {(1,1),2,2), .......(20,20)}
$∴$ Points within $Δ O B C$ and $Δ A B C$ = 400 - 20 = 380
By symmetry points within $Δ O A B = \frac{380}{2} = 190$