wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of integral solution of x+y+z+t=29, when x1,y>1,z>2,to

Open in App
Solution

Given,x+y+z+t=29.......whenx1,y2,z3andt0thetotaldistinctobject=29,distributeintox,y,z,andtx1y2z3then,remaning=296=23Now,No.ofways=n+r1Cr1withoutanyconditiondistributeintox,y,z,t=23+41C41=26C3=|!26|!3|!23=26×25×24×|!233×2×1×|!23=2600
so, the Answer is 2600.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometric Representation and Trigonometric Form
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon