The number of integral solutions for the equation x+y+z+t=20, where x,y,z,t≥−1, is
A
20C4
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B
23C3
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C
27C4
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D
27C3
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Solution
The correct option is D27C3 Given x+y+z+t=20 x≥−1,y≥−1,z≥−1 and t≥−1
Put x+1=x1,y+1=x2,z+1=x3,t+1=x4 (where x1,x2,x3,x4≥0)
Hence given equation becomes x1+x2+x3+x4=24 ∴ Number of non-negative integral solutions =(24+4−1)C4−1=27C3