The number of integral solutions of x+y+z=0 with x≥−5,y≥−5,z≥−5 is
A
134
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B
136
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C
138
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D
140
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Solution
The correct option is B136 Let x=p−5,y=q−5 and z=r−5, where p,q,r≥0. Then the given equation reduces to p+q+r=15⋯(1) Now, we have to find non-negative integral solution of Eq. (1). The total number of such solutions is 15+3−1C3−1=17C2=136.