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Question

The number of integral solutions satisfying the equation log2x112log2(x3)+2>0 is equal to

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Solution

log2x112log2(x3)+2>0
log2x132log2(x)+2>0[logxm=mlogx]
Let log2x be t2+1.
the question looks like t32(t2+1)+2>0
2t3t23+4>0
3t22t1<0
3t23t+t1<0
(t1)(3t+1)<0
So, t(13,1)
Hence, log2x(109,2)
So, x(2109,4)(21.11111,4)(2.16,4)
In this range, only one integer exists, i.e. 3

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