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Question

The number of integral terms in the expansion of (71/3+111/9)6561 is

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Solution

Tr+1= 6561Cr (713)6561r(1119)r= 6561Cr 7(2187r3)11(r9);
r must be multiple of 9.
r=0,9,18,,65616561=0+(k1)×9k=730


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