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Byju's Answer
Standard XII
Mathematics
Sufficient Condition for an Extrema
The number of...
Question
The number of integral values in the solution set of the inequation
|
x
−
1
|
+
|
x
−
2
|
+
|
x
−
3
|
<
0
is
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Solution
Given:
|
x
−
1
|
+
|
x
−
2
|
+
|
x
−
3
|
<
0
We know that modulus always will give
positive value, so-
|
x
−
1
|
+
|
x
−
2
|
+
|
x
−
3
|
<
0
(all positive)
so, sum at '3' positive quantities never can be
negative. So there is no solution for
this equation. It means zero integral value
in the solution set of given equation.
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Similar questions
Q.
If the solution set of
|
x
−
k
|
<
2
is a subset of the solution set of the inequality
2
x
−
1
x
+
2
<
1
,
then the number of possible integral value(s) of
k
is
Q.
l
o
g
(
x
−
2
)
(
2
x
−
3
)
>
l
o
g
(
x
−
2
)
(
24
−
6
x
)
The solution set of the above inequality has integral values of x
___
Q.
If the solution set of
|
x
−
k
|
<
2
is a subset of the solution set of the inequality
2
x
−
1
x
+
2
<
1
,
then the number of possible integral value(s) of
k
is
Q.
l
o
g
(
x
−
2
)
(
2
x
−
3
)
>
l
o
g
(
x
−
2
)
(
24
−
6
x
)
The solution set of the above inequality has integral values of x
___
Q.
Find the number of integral values of
a
so that the inequation
x
2
−
2
(
a
+
1
)
x
+
3
(
a
−
3
)
(
a
+
1
)
<
0
is satisfied by atleast one
x
∈
R
+
.
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