The number of integral values of a, a∈(6,100) for which the equation [tanx]2+tanx−a=0 has real roots (where [.] denotes greatest integer function) is:
A
7
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B
8
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C
5
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D
4
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Solution
The correct option is A 7 aϵ(6,100),[tanx]2+tanx−a=0[tanx]2+tanx=a,foratobeintegral,tanxshouldbeintegral.tanx=1and2,a=2and6,rejected.tanx=3,4,5,6,7,8,9;a=12,20,30,42,56,72,90.So,7values