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Question

The number of integral values of a for which (a23a+2)x2+(a25a+6)x+a24=0 is an identity in x is

A
0
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B
2
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C
1
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D
3
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Solution

The correct option is B 1
If this given equation is identity than a23a+2=0, a=2,1
a25a+6=0, a=3,2
a24=0, a=2,2
So, common value of a=2
Hence, option 'C' is correct.

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