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Question

The number of integral values of p, for which the equation 5cosx+4sinx=2p+3 has real solutions is

A
2
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B
8
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C
4
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D
6
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Solution

The correct option is D 6
5cosx+4sinx=2p+3
For the equation to have solution, 2p+3 should lie in the range of 5cosx+4sinx

Now, 52+425cosx+4sinx52+42
52+422p+352+42412p+3414132p4134132p4132

Hence, the integral values of p are {4,3,2,1,0,1}

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