wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of integral values of p, for which the equation 5cosx+4sinx=2p+3 has real solutions is

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 6
5cosx+4sinx=2p+3
For the equation to have solution, 2p+3 should lie in the range of 5cosx+4sinx

Now, 52+425cosx+4sinx52+42
52+422p+352+42412p+3414132p4134132p4132

Hence, the integral values of p are {4,3,2,1,0,1}

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Range of Trigonometric Expressions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon