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Question

The number of integral values that k can take if x2+kxk2+5k>0 for all xR, is

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Solution

The given quadratic equation is x2+kxk2+5k>0
Here, a=1,b=k,c=k2+5k
Since, x belongs to real number.
b24ac=0
(k)24(1)(k2+5k)=0
k2+4k220k=0
5k220k=0
k(5k20)=0
k=0 and 5k20=0
k=0,4

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