The number of intersection points of diagonals of $2009$ sides polygon, which lie inside the polygon.

^{2009} C_{4}

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^{2009} C_{2}

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^{2008} C_{4}

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^{2008} C_{2}

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Solution

The correct option is C $^{2009} C_{4}$
Choosing any $4$ vertices make $1$ intersection

$∴$ No. of intersection points of diagonals $=^{n} C_{4}$

Here $n = 2009$ , No. of points $=^{2009} C_{4}$

$∴$ Option $A$ is correct.

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The number of intersection points of diagonals of 2009 sides polygon, which lie inside the polygon.

The correct option is C 2009C4Choosing any 4 vertices make 1 intersection ∴ No. of intersection points of diagonals =nC4Here n=2009, No. of points =2009C4∴ Option A is correct.

The number of intersection points of diagonals of $2009$ sides polygon, which lie inside the polygon.

The correct option is C $^{2009} C_{4}$
Choosing any $4$ vertices make $1$ intersection

$∴$ No. of intersection points of diagonals $=^{n} C_{4}$

Here $n = 2009$ , No. of points $=^{2009} C_{4}$

$∴$ Option $A$ is correct.