The number of ions formed in an aqueous solution by the complex $[C o (N H_{3})_{6}] C l_{3}$ is

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Solution

The correct option is D 4
The $C l^{-}$ ion is outside the coordination sphere, and there are 3 such ions.
We should have a total of four ions in solution and the 4th being the complex cation. The equation can be seen below,
$[C o (N H_{3})_{6}] C l_{3} \to [C o (N H_{3})_{6}]^{3 +} + 3 C l^{-}$

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Similar questions

[C o (N H_{3})_{6}] C l_{3}

[C o (N H_{3})_{6}] C l_{3}

The number of ions per mole of the complex [Co(NH₃)₆]Cl₃ in solution will be:

[C o (N H_{3})_{6}] C l_{3}

M A g N O_{3}

0.3

[C o (N H_{3})_{6}] C l_{3}

M [C o (N H_{3})_{6}] C l_{3} = 267.46 g/mol

M_{A g N O_{3}} = 169.87 g/mol

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