Question

The number of ions formed when cuprammonium sulphate is dissolved in water is:

• A. Zero
• B. $1$
• C. $2$
• D. $4$

Answer 1

The correct option is C $2$

Cuprammonium salt is $\left[Cu{\left({NH}_3\right)}_4\right]{SO}_4$. In water it gives two ions, ${\left[Cu{\left({NH}_3\right)}_4\right]}^{2+}$ and ${SO}_4^{2-}$