Question

The number of ions formed, when tris(ethane-1,2-diamine)copper$\left(II\right)$ sulphate is dissolved in water will be:

Answer 1

The formula of tris(ethane-1,2-diamine)copper$\left(II\right)$ sulphate is $\left[Co\right(en{)}_3]S{O}_4$. When it dissolved in water, it forms $\left[Co\right(en{)}_3{]}^{2+}$ and $S{O}_4^{2-}$. So, two ions will be formed.