The number of ions present in K 3- F e CN 6- areA- 3B- 2C- 10D- 4

The correct option is D 4 K_3[Fe(CN)_6] ⇌ 3K+ + [Fe(CN)_6]^3 i.e., 4 ions ...

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Werner's Coordination Theory

The number of...

Question

The number of ions present in $K_{3} [F e (C N)_{6}]$ are

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K_{3} [F e (C N)_{6}]

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K_{4} [F e {(C N)}_{6}]

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C o C l_{3} ∙ 4 N H_{3}

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